### RE: Divide the number 395 into three different parts such that the second part is 25 % more than the first part and 20 % more than the third part.

Divide the number 395 into three different parts such that the second part is 25 % more than the first part and 20 % more than the third part.

a . 125, 150, 120

b. 120, 125, 150

c. 120, 150, 125

d. 125, 120, 150

e. None of the above

Thanks for your questions,

your problem is – **Divide the number 395 into three different parts such that the second part is 25 % more than the first part and 20 % more than the third part.**

**Which answer is correct?
a . 125, 150, 120
b. 120, 125, 150
c. 120, 150, 125
d. 125, 120, 150
e. None of the above**

It is a very easy question,

**Your Correct answer: c**

Read this Explanation very carefully According to the question, Hope you will get clear Idea:

According to the question,

Second part is 25 % more than the first part ………….i

Second part is 20 % more than the third part ………..ii

Let the third part = x …………iii

∴ The second part = x = 20 % of x

∴ The second part = x + (x/5) = 6x/5 = 1.20x …………iv

Similarly, the first part = 1.20x – 25 % of 1.20x

∴ The first part = 0.96x ………..v

But, the sum of all the three parts = 395 ………….vi

∴ From equations iii, iv, v and vi, we can say that,

x + 1.20x + 0.96x = 395

∴ x = 125 = third part

∴ Second part = 1.20 * x = 150

And, the first part = 0.96 * x = 120

**Hence, the correct answer is option c**

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