# Find the dividend if it is given that the dividend when divided by 6 gives the remainder as half of the divisor and the quotient is 2 more than the perfect square of the divisor.?

Find the dividend if it is given that the dividend when divided by 6 gives the remainder as half of the divisor and the quotient is 2 more than the perfect square of the divisor.?

a. 123
b. 321
c. 345
d. 123
e. 231

Your question is –
Find the dividend if it is given that the dividend when divided by 6 gives the remainder as half of the divisor and the quotient is 2 more than the perfect square of the divisor?

See the details Explanation of your question:

According to the question,
Divisor = 6….. (i)
Quotient = 2 + perfect square of the divisor
Thus, quotient = 2 + 36 = 38…..(ii)
Remainder = half of the divisor
Thus, remainder = 6/2 = 3…..(iii)
According to the standard mathematical formula for division:
Dividend = divisor * quotient + remainder
Substituting the values from equation (i), (ii) as well as (iii) in this formula, we get,
Dividend = 6 * 38 + 3
∴ Dividend = 228 + 3
∴ Dividend = 231

Hence, the correct answer is option e.